以下使用 Objective C，将 url 的NSString格式的请求参数部分，转换为字典NSDictionary对象，方便对参数进行访问。

代码实现

提取 url 中需要处理的字符串：从问号 ? 开始，到锚部分（从 # 号开始的部分）。字符串以 & 符号分开成键值对，开始拼接存入键类。以下方法通用适应于 IOS 项目。

// 解析 url 字符串为 dictionary
- (NSMutableDictionary *)parseUrlQuery2Diction:(NSString *)url {
    NSMutableDictionary *queryStringDictionary = [[NSMutableDictionary alloc] init];
    NSRange range = [url rangeOfString:@"?"];
    if (range.location == NSNotFound) {
        return queryStringDictionary;
    }
    url = [url substringFromIndex:(range.location + 1)];
    range = [url rangeOfString:@"#"];
    if (range.location != NSNotFound) {
        url = [url substringToIndex:(range.location)];
    }
    NSArray *urlComponents = [url componentsSeparatedByString:@"&"];
    for (NSString *keyValuePair in urlComponents)
    {
        NSArray *pairComponents = [keyValuePair componentsSeparatedByString:@"="];
        NSString *key = [[pairComponents firstObject] stringByRemovingPercentEncoding];
        NSString *value = [[pairComponents lastObject] stringByRemovingPercentEncoding];
        if ([key length] == 0) {
            continue;
        }
        [queryStringDictionary setObject:value forKey:key];
    }
    return queryStringDictionary;
}

调用示例

NSString *url1 = @"https://localhost:8080/test";
NSDictionary * params1 = [self parseUrlQuery2Diction:url1];
NSLog(@"params1: %@", params1);
NSString *url2 = @"https://localhost:8080/test?a=1&b=2";
NSDictionary * params2 = [self parseUrlQuery2Diction:url2];
NSLog(@"params2: %@", params2);
NSString *url3 = @"https://localhost:8080/test?c=3&d=4#xyz";
NSDictionary * params3 = [self parseUrlQuery2Diction:url3];
NSLog(@"params3: %@", params3);

运行的结果：

params1: {
}
params2: {
    a = 1;
    b = 2;
}
params3: {
    c = 3;
    d = 4;
}